View Single Post
Old 01-28-2003, 10:58 PM   #8
Hethj7
Mizzou Tigers
 
Hethj7's Avatar
 
Join Date: Apr 1999
Location: weston, MO United States
Posts: 1,455
Default

Thanks for the link Deuce! That one I found using google is pretty good too (check out the link in my previous post).

Anyway, here was the original problem (if anyone cares at this point).

Water at 60 degrees (F) is to be pumped into a tank that is 150 feet above the pump. The pipe is 1000 feet long and 12 inches in diameter. Friction factor is .025 and neglect entrance and exit losses. Plot head pressure (in feet of water) vs. discharge flow rate, Q (gal/min).

Using the energy equation and Continuity equation Q=AV, then simplifying:

head pressure = change in elevation + (friction factor) * (length/diameter) * (4Q/(pi*d^2)) * 1/(2g)

This equation is correct, as we did it in class. I guess my main problem comes from getting value for g , 32.2 ft/s^2. I can't figure out how to get rid of the s^2 so that I can be left with just values for gal/ min.

Well, if anyone actually read through all this, sorry I bored you to death. For anyone else who may actually have an idea, I am all ears !
__________________
2006 Mustang GT

1990 LX
GT-40 motor 262 horsepower, 307ft-lbs (sold but forever loved)

1998 Contour SVT

Rice Haters Club Member #244
Hethj7 is offline   Reply With Quote