Quote:
Originally posted by Hethj7
Thanks for the link Deuce! That one I found using google is pretty good too (check out the link in my previous post).
Anyway, here was the original problem (if anyone cares at this point).
Water at 60 degrees (F) is to be pumped into a tank that is 150 feet above the pump. The pipe is 1000 feet long and 12 inches in diameter. Friction factor is .025 and neglect entrance and exit losses. Plot head pressure (in feet of water) vs. discharge flow rate, Q (gal/min).
Using the energy equation and Continuity equation Q=AV, then simplifying:
head pressure = change in elevation + (friction factor) * (length/diameter) * (4Q/(pi*d^2)) * 1/(2g)
This equation is correct, as we did it in class. I guess my main problem comes from getting value for g , 32.2 ft/s^2. I can't figure out how to get rid of the s^2 so that I can be left with just values for gal/ min.
Well, if anyone actually read through all this, sorry I bored you to death. For anyone else who may actually have an idea, I am all ears  !
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geez...that looks like a problem i would do that mixes my calc2 class with my physics class...i hate that stuff...
friction factor...good ole u (close the the u anyways)...
youre making me wonder why im a physics major..lol..i want out!
