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tire diameter?
225/50-15 whats my tire diameter in inches? And the formula?
------------------ Ford Mustang -87 With K&N filter and walker exhaust.14,61 and 95,5. 4,10 rear before june 2001. |
It's width times aspect ratio divided by 1270 + wheel size.
(225 x 50) / 1270 + 15 = 23.86. ------------------ 351W 89 Mustang GT Convertible |
Jimberg, that is a good and easy formula. Is the 1270 a constant? Just wondering were that (1270) came from.
I usually do a rough figure, 225/25 x .5 x 2 + 15 = 24. The reason that is rough is that 25mm is not exactly an inch, its 24.??. Your formula looks to be exact and much easier. ------------------ Rick My 89lx(updated 2/21/2001) My 97 Cobra |
The 1270 is half of 2540. There are 25.4 mm to an inch. Since I don't treat the aspect ratio as a percentage, I make up for it in the conversion factor. Also, since dividing by 2540 would give you the sidewall height, I divide it by 2 to get 2 times the sidewall height. Then you just add that to the wheel height.
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Ahhh... the 1270 isn't a constant. I should have been able to come to that conclusion. So the formula is tire width divided by ratio times 2 plus rim size.
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Actually I don't know what I'm thinking. Its the same formula you where just more exact and made it simple for him...
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It's a simplification of the formula:
( ( <Tire Width> * <Aspect Ratio> / 100 ) / 25.4 ) * 2 + <Wheel Diameter> 1270 is a constant. |
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