Actually the coil-over difference is a factor of 4! (for the front).
Torque = force * distance
Force = (spring constant) * compression
The compression is proportional to the radius. ie. circumference = 2pi*r
So, Torque = k (dist) * compression
Since you're doubling the leverage & the compression, it's equivalent to 4X that of the stock location. (Actually is something like 4.1 because the springs aren't vertical... so they're compressed even more than what the arm movement would indicate).
So a 250# coil-over is similar to a 1000# spring in the stock location. Fortunately, the unsprung weight is reduced and the spring's motion becomes the same as the strut's, so the ride is a little better.
So with coil-overs, you have to take the square of the ratio.
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