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Originally posted by 86 Grand Marqui
Ok, 1 at a time,1..Nothing I have has an s at the end of the name,2..I live in the city,we race in the woods,3..I did not start the Probe Thread,4..No idea what"Ricer" means.5..A "Flag Man" Race is a Race with a guy in front of the 2 cars that has his arms up, then drops to start the race, in theory.6..You are correct, I need New exhaust,7..It's My Car,8..I wish I could hit 18 mph in 60'.9..Noone is going to touch me,and it doesnt take but a few minutes to set up the more difficult races,10.. @the Dirt Road thing.11..Welcome Back.
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Dude. Listen. You're the math wiz who can figure out the necessary lengths to beat somebody, right?
60ft. 2.19sec. 60/2.19 = 27.40ft/s. That's your average speed. 27.40ft/s = 18.7mph. Do you understand that bunch of VERY VERY simple math? That's your average speed needed to cover 60ft in 2.19sec. Average, meaning since you're accelerating you MUST go faster than 18mph by the end of 60ft, or it's impossible for you to 60ft in 2.19sec. Taking that astute observation made by me into account, and assuming a linear rate of speed increase, you'll be going 0 at 0ft, 18mph at 30ft and 36mph at 60ft. There are obvious flaws in such linear math because the car doesn't accelerate or cover ground in a linear fashion, instead it covers ground at an exponential rate. Meaning accleration would be closer to d = st^x where d = distance, s = a variable t = time and x = variable.