drivetrain loss????

[Hethj7]

Originally posted by bigwhitecobra
Double the power and the load stays the same, the more work can be done, as in pushing the car. I may be going in the wrong direction, but this is how I see it. Later.

That is my point. In an engine the load does not stay the same. The friction is providing the load in the drivetrain, and friction is directly proportional to to power (force). Therefore, more power gives more friction, which leads to a larger load that must be overcome.

Again, friction = coefficient of friction X the force normal to the surface. A greater force will give more friction to overcome.


I could be wrong in that this doesn't apply in an engine, but it is my theory.